Question

find the value of 21x³-63x²+3for x=4​

Answer 1

Answer:

=339

Step-by-step explanation:

$21 {x}^{3} - 63 {x}^{2} + 3$

for x=4

$21 {(4)}^{3} - 63 {(4)}^{2} + 3$

= 1344 -1008+3

= 339