Math, asked by nimmigrover03, 29 days ago

find the value of 2²y+2 = 16²y - 1​

Answers

Answered by aWitSu
1

Answer:

y=\frac{1}{84}

Step-by-step explanation:

2^2y+2=16^2y-1

4y+2=16^2y-1

4y+2=256y-1

4y+2-2=256y-1-2

4y=256y-3

4y-256y=256y-3-256y

-252y=-3

\frac{-252y}{-252}=\frac{-3}{-252}

y=\frac{1}{84}

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