Question

.
Find
the value of:
[(23+2^2)^2/3+ (140- 19)^1/2]​

Answer 1

HELLO MATE

Answer: 400

Step by step explanation:

[ ( 23+2² )⅔ + ( 140 - 19 ) ½ ] ²

==> [ ( 23 + 4 ) ⅔ + ( 121 ) ½ ] ²

==> [ 27 ⅔ + ( 11² )½ ] ²

==> [ ( 3³)⅔ + ( 11 ) ] ²

==> [ 3² + 11 ]²

==> [ 9 + 11 ]²

==> 20 ²

==> 20 × 20

==> 400

HOPE THIS HELPS YOU

PLEASE FOLLOW ME ✌️

Answer 2

Step-by-step explanation:

(23+2²)^⅔+(140-19)^1/2

=(23+4)^⅔+(121)^½

= 27^⅔+ 121^½

= 9+ 11

= 20.

Hope it helps

Mark me as brainliest.