Question

find the value of 23^2 and 51^2 by using exp​

Answer 1

Step-by-step explanation:

(23) ^2 (a+b) ^2=a^2+2ab+ b^2

=(20+3) ^2

= (20)^2+2(20) (3) +(3) ^2

=400+120+9

=529

(51) ^2 (a+b) ^2=a^2+2ab+ b^2

(50+1) ^2

= (50)^2+2(50) (1) +(1) ^2

=2500+100+1

=2601