find the value of {(23+2²)⅔+(140-19)½}²
Anonymous:
25^2=625 .............. 625^2/3 = 5^2 = 25..............................121^1/2=11..............(25+11)^2 = 36^2
1296 is the ans!
I can't understand
ok i am answering it wait !
it wud be 400 i read the question wrong !
Answers
Answered by
35
={(23+4)^2/3+(140-19)^1/2}^2
={(27)^2/3+(121)^1/2}^2
={(3^3)^2/3+(11^2)^1/2}^2
={3^2+11}^2
=(9+11)^2
=20^2
=400
={(27)^2/3+(121)^1/2}^2
={(3^3)^2/3+(11^2)^1/2}^2
={3^2+11}^2
=(9+11)^2
=20^2
=400
Answered by
33
Answer:
Step-by-step explanation:
[ ( 23+2² )⅔ + ( 140 - 19 ) ½ ] ²
==> [ ( 23 + 4 ) ⅔ + ( 121 ) ½ ] ²
==> [ 27 ⅔ + ( 11² )½ ] ²
==> [ ( 3³)⅔ + ( 11 ) ] ²
==> [ 3² + 11 ]²
==> [ 9 + 11 ]²
==> 20 ²
==> 20 × 20
==> 400
The value is 400
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