Question

find the value of:-​

Answer 1

Answer:

Correct answer is:5 root of x to the power a square-b square-c square.

That's it.

Answer 2

$\sf\large\green{ } \sqrt[5]{ {x}^{a - b} } \times \sf\large\green{ } \sqrt[5]{ {x}^{b - c} } \times \sf\large\green{ } \sqrt[5]{ {x}^{c - a} } \\ \sf\large\green{ \sqrt[p]{q} = {q}^{ \frac{1}{p} } } \\ = > \sf\large\green{ }( { {x}^{a - b}) }^{ \frac{1}{5} } \times \sf\large\green{ } {( {x}^{b - c}) }^{ \frac{1}{5} } \times \sf\large\green{ } { ({x}^{c - a} )}^{ \frac{1}{5} } \\ \\ = > \sf\large\green{ } ({x}^{ \frac{a}{5} - \frac{b}{5} } ) \times ( {x}^{ \frac{b}{5} - \frac{c}{5} } ) \times ( {x}^{ \frac{c}{5} - \frac{a}{5} } ) \\ \\ \sf\large\green{ {p}^{x} + {p}^{y} + {p}^{z} = {p}^{(x + y + z)} } \\ \\ \sf\large\green{ } = > {x}^{ (\frac{a}{5} - \frac{b}{5} ) + (\frac{b}{5} - \frac{c}{5}) + (\frac{c}{5} - \frac{a}{5} ) } \\ \\ = > \sf\large\green{ } {x}^{( \frac{a}{5} - \frac{a}{5} ) + (\frac{ b}{5} - \frac{b}{5} ) + (\frac{c}{5} - \frac{c}{5}) } \\ \\ = > \sf\large\green{ } {x}^{0} \\ \\\sf\large\green{ {p}^{0} = 1} \\ \\ = > \sf\large\red{1 }$

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Hope it will help uh...

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