Question

find the value of 25x^2 + 16y^2 + 40 xy at x=1 and y=-1.​

Answer 1

Answer: Given:- x = 1 & y = -1

Putting the value given in the equation, 25x² + 16y² + 40xy , we get:

=> 25x² + 16y² + 40xy

=> 25(1)² + 16(-1)² + 40(1)(-1)

=> 25 + 16 -40

=> 41 - 40

=> 1

Hence, 25x² + 16y² + 40xy = 1

I hope it helps u