Find the value of 25x^2 + 36y^2, if (5x + 6y) = 21 and xy = 3.
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Answer:
Ans :- 261
Step-by-step explanation:
25x^2+36x^2 if (5x+6y)=21
=(5x)^2 + (6x)^2
=(5x+6y)^2 - 2•5x•6y
= (21)^2 - 60xy
=441-60•3
=441-180
=261
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