Question

Find the value of √27 +√75 +√48 – √108 if √3=1.7.
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Answer 1

Answer:

$= \sqrt{27} + \sqrt{75} + \sqrt{48} - \sqrt{108} \\ = \sqrt{3 \times 3 \times 3} + \sqrt{5 \times 5 \times 3} + \sqrt{4 \times 4 \times 3} - \sqrt{3 \times 3 \times 3 \times 2 \times 2} \\ = 3 \sqrt{3} + 5 \sqrt{3} + 4 \sqrt{3} - 6 \sqrt{3} \\ = 12 \sqrt{3} - 6 \sqrt{3} \\ = 6 \sqrt{3} = 6 \times 1.7 = 10.2$

ans.=10.2

Step-by-step explanation:

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