find the value of 27 power 1 by 3 into 16 power minus 1 by 4
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27^(1/3) x 16^(-1/4) = 2^(3x1/3) x 2(4x(-1/4))
= 2^1 x 2^(-1) = 2/2 = 1
(We know that 27= 3^3 & 16 = 2^4)
rakesh5758:
this not answer
Answered by
1
Answer:
Step-by-step explanation:
27^1/3 x 16^-1/4
= [(3)^3]^1/3 x [(2)^4]^-1/4
= (3)^3x1/3 x (2)^4x(-1)/4
= 3 x 2^-1
=3 x 1/2
Ans.=3/2
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