Find the value of 27x^3 - 64y^3 - 108x^2y + 144xy^2 if x = 3 and y 2.
Answers
Answered by
0
Just expand it.
(3x - 4y)^3 = (3x)^3 - (4y)^3 + 3×(3x)^2×(-4y) + 3×3x×(-4y)^2
= 27x^3 - 64y^3 - 108x^2y + 144xy^2
So
a = -108
b = 144
a+b = -108 + 144 = 36
Answered by
15
Answer:
(3x + 4y)3 is the answer
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