Math, asked by manishpandey10, 1 year ago

find the value of 27x^3+64y^3 if 3x+4y=0and xy=12.

Answers

Answered by vinay0018

3

To find 27x^3+64y^3
x^3+y^3=(x+y) (x^2+2xy+y^2)
x=3x
y=4y
(3x+4y)(3x^2+2*xy+4y^2)
0(9x^2+2*12+16y^2) any number multipled by 0 is 0
So x^3+y^3=0

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