Find the value of 27x^3+8y^3 if 3x+2y=20 and xy=11/9
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Answer:
13260
Explanation:
xy=11/9........(1)
therefore X=11y/9 ......(2)
since 3x+2y=20
27x^3+8y^3
= (3x)^3+(2y)^3
=(3x+2y)(9x^2 -xy+4y^2)
=(20)((3x+2y)^2-2xy-2xy)....... (from 2)
=(20)((20)^2-3×11/9).....(from 1,2)
=(20)(400-11/3)
=20×1989/3
=20×663
=13260
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