Find the value of 27x^3 + 8y^3,if 3x+2y=20and xy=11/9
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(3x)^3+(2y)^3= (3x+2y)[(3x)^2+(2y)^2-3x*2y]
=(3x+2y)[(3x+2y)^2-2*3x*2y-3x*2y]
=20(20-12*11/9-6*11/9)
=20[(180-132-66)/9]
=20* (-2)
=-40
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