Math, asked by ashvathrajesh78, 1 month ago

Find the value of 27x^3+8y^3 when 3x+2y = 20 and 9 = 11

Answers

Answered by pihu4976
1

Answer:

Hope it helps you!!

Step-by-step explanation:

27x³ + 8y³

= (3x)³ + (2y)³

= (3x +2y)³ - 3 × 3x × 2y (3x +2y)

= ( 3x +2y)³ - 18 xy(3x + 2y)

= (20)³ - 18 ×11 (20)

= 8000 -198 × 20

= 8000 - 3960

= 4040

Similar questions