find the value of 27x³-64y³-108x²y+144xy² if x=3,y=2
Answers
Answered by
4
Answer:23(3) ^3-64(2)^3-108(3) ^2(2) +144(3) (2) ^2
23(27) -64(8) -108(9) (2) +144(3) (4)
621-512-1944+1728
193
Hope it will help
Step-by-step explanation:
Answered by
5
Answer:
According to your question .
we have to find the value by putting x as 3 and putting y as 2
.. To solve this we will factorise it first
To factorise it , we will use the identity
(a-b)³ = a³-3a²b+3ab²-b³
(a-b)³ = a³-b³-3a²b+3ab²
27x³-64y³-108x²y + 144xy²
(3x)³-(4y)³-3×(3x)²×(4y)+3×(3x)×(4y)²
= (3x-4y)³
now putting down value of x and y
(3x-4y)³ ,
x = 3 and y = 2
(3×3 - 4×2)³
= (9 - 8)³
= (1)³ = 1
Answer = 1
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