Math, asked by ravi7377, 11 months ago

find the value of 27x³-8y³ if 3x-2y=11 andxy=12​

Answers

Answered by chnageswarr
0

Step-by-step explanation:

3x-2y =11

( 3x-2y )^3 = 11^3

( 3x )^3- ( 2y )^3- 3{3x}{2y}{3x-2y} = 1331

27x^3 - 8y^3 - 18(xy)(11) = 1331

27x^3 - 8y^3- 198(12) = 1331

27x^3 - 8y^3 = 1331 + 2376

= 3707

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