Math, asked by tengramtangram, 4 months ago

find the value of (28)^3+(-15)^3+(-13)^3​

Answers

Answered by bishtsmita06
2

Answer:

16380

Step-by-step explanation:

We know that,

If (a+b+c)=0, then a³+b³+c³ =3abc

Here, 28+(−15)+(−13)=0

28³+(−15)³+(−13)³ = 3(28)(−15)(−13)=16380

Answered by 726211
2

Answer:  have to find the value :=> (28)³ + (–15)³ + (-13)³ Let -» a = 28 b -» -15 c -» -13 = > a + b + c = 0 ... (28)³+(-15)³+(-13)³,Without actual calculating the cubes, find the value of it. ... 28)³+ (–15)³ + (-13)³ = 3(28)(-15)(-13) = 16380

Step-by-step explanation:

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