Question

find the value of 2a^2 +3b^2+4c^2 when a =1,b=1 and c=0​

Answer 1

GIVEN★

• $= 2a {}^{2} + 3b {}^{2} + 4c {}^{2}$

FIND★

• $= 2a {}^{2} + 3b {}^{2} + 4c {}^{2}$
• when

• a=1 , b=1 , c=0

EVLUATION★

• $= > 2a {}^{2} + 3b {}^{2} + 4c {}^{2} - - (1)$

• when a=1 , b=1 , c=0 ------------(2)

• eq 2 value put on eq (1)

• $= > 2(1) {}^{2} + 3(1) {}^{2} + 4(0) {}^{2} \\ \\ \\ = > 2 \times 1 + 3 \times 1 + 4 \times 0 \\ \\ \\ = > 2 + 3 + 0 \\ \\ \\ = 5$

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answer★

$= 5$

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learn more★

• $= > (0) {}^{n} = 0 \\ \\ \\ = > n \times 0 = 0 \\ \\ \\ = > n + 0 = n \\ \\ = > (1) {}^{n} = 1 \\ \\ \\ = > n\times 1 = n$
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I hope it helps