Question

Find the value of (2cos 67)/(sin 23)​

Answer 1

Answer:

(2cos 67)/(sin 23)

=2cos67/sin(90-67)

=2cos67/cos67

=2

Answer 2

Step-by-step explanation:

Cos(67)-sin(23).

=cos(π/2-23)-sin(23).

=sin(23)-sin(23). [cos(π/2-23)=sin(23)

=0

OR

cos^2 67−sin^2 23

This can be written as:

sin^2(90–67) -sin^2 23

[As sin(90–α)=cos α]

So, sin^2 23−sin^2 23=0

Thus,the answer is 0.