find the value of 2pq+qr -3pr if p=-2 q=-3 and r=1
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Answered by
1
Answer:
p
2
−q
2
)x
2
+(q
2
−r
2
)x+r
2
−p
2
=0 ....(1)
The sum of the coefficients (p
2
−q
2
)+(q
2
−r
2
)+(r
2
−p
2
)=0
Therefore, x=1 is a root of equation 1.
(p
2
−q
2
)y
2
+(r
2
−p
2
)y+q
2
−r
2
=0 .....(2)
p
2
−q
2
+r
2
−p
2
+q
2
−r
2
=0
Therefore, y=1 is a root of equation 2.
Therefore, 1 is the common root of equations 1 and 2.
Answered by
0
Answer:
15
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