Math, asked by roymanishkumar229, 4 months ago

find the value of 2pq+qr -3pr if p=-2 q=-3 and r=1​

Answers

Answered by nehaasahh
1

Answer:

p

2

−q

2

)x

2

+(q

2

−r

2

)x+r

2

−p

2

=0 ....(1)

The sum of the coefficients (p

2

−q

2

)+(q

2

−r

2

)+(r

2

−p

2

)=0

Therefore, x=1 is a root of equation 1.

(p

2

−q

2

)y

2

+(r

2

−p

2

)y+q

2

−r

2

=0 .....(2)

p

2

−q

2

+r

2

−p

2

+q

2

−r

2

=0

Therefore, y=1 is a root of equation 2.

Therefore, 1 is the common root of equations 1 and 2.

Answered by saumyabiju
0

Answer:

15

Step-by-step explanation:

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