Math, asked by snksharma4321, 5 months ago

Find the value of 2sin^2 30° + tan60° - 3cos^2 60 °

Answers

Answered by amanraj56
0

Step-by-step explanation:

2sin²30° + tan60° - 3cos² 60

2(1/2)²+√3-3(1/2)²

(2×1/4)+√3-(3×1/4)

2/4-3/4+√3

-1/4+√3

√3-1/4

#666

Answered by diyalakhera1507
0

Answer:

sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/-2sin-2-30-tan60-3cos-2-60-sec-2-30

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