find the value of 2sin^2 30° tan60°-3cos^2 60°
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Answered by
1
Answer:
2sin²30° x tan60° - 3cos²60°
2x1/4 x √3 - 3x1/4
1/2 x √3 x 3/4
3√3/8
Answered by
0
Answer:
2sin^2 30°tan60°-3cos^2 60°
=2(1/2)^2×(√3)-3(1/2)^2
=2(1/4)×(√3) -3(1/4)
=(2/4)×√3 -(3/4)
=(1/2) ×√3 -(3/4)
=(√3/2) -(3/4)
=(2√3-3)/4 [Ans.]
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