find the value of 2sin²20-2tan²45°+3sin²70°
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Answer:
1
Step-by-step explanation:
3sin²20°-2tan²45°+3sin²70°
=3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}²
=3sin²20°-2×(1)²+3cos²20°
=3(sin²20°+cos²20°)-2
=3-2 [∵, sin²20°+cos²20°=1]
=1
Hope it helps!!!
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