Question

Find the value of 2sin²45° + cos²45° . *
(A) ½
(B) 3/2
(C) √3/2
(D) 3/√2​

Answer 1

$= 2 { \sin}^{2} 45 + { \cos }^{2} 45 \\ = 2 \times {(\frac{1}{ \sqrt{2} } )}^{2} + { (\frac{1}{ \sqrt{2} } )}^{2} \\ = 2 \times \frac{1}{2} + \frac{1}{2} \\ = 1 + \frac{1}{2} \\ = \frac{3}{2}$

Option (B) is correct !