Question

Find the value of 2sinAsinB

Answer 1

Answer:

2sinAsinB=cos(A-B)-cos(A+B)

Step-by-step explanation:

cos(A-B)=cosAcosB+sinAsinB,

cos(A+B)=cosAcosB-sinAsinB,

Adding both we get,

2sinAsinB=cos(A-B)-cos(A+B)

Answer 2

cos (a-b) - cos (a+b)

it is solution hope its help u