Find the value of 2sinAsinB
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Answer:
2sinAsinB=cos(A-B)-cos(A+B)
Step-by-step explanation:
cos(A-B)=cosAcosB+sinAsinB,
cos(A+B)=cosAcosB-sinAsinB,
Adding both we get,
2sinAsinB=cos(A-B)-cos(A+B)
Answered by
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cos (a-b) - cos (a+b)
it is solution hope its help u
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