Math, asked by sonamuddeshaya, 6 hours ago

Find the value of :

‌ 2x+1 3
7 ÷ 49 = 7​

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Answers

Answered by aliabidi09
1

Step-by-step explanation:

 \frac{ {7}^{2x + 1} }{ {7}^{2} }  =  {7}^{3}

 \frac{ {7}^{2x + 1 - 2} }{1}  =  {7}^{3}

 {7}^{2x - 1}  =  {7}^{3}

Bases same so Power should be equal

2x - 1 = 3

2x = 3 + 1

2x = 4

x =  \frac{4}{2}

x = 2

Answered by Zaeem7Ch
1

Answer:

Answer is 2

Step-by-step explanation:

7*2x+1 ÷ 49 = 7*3

7*2x+1 ÷ 7*2 =7*3

7*2x+1=7*3×7*2

7*2x+1=7*5

as bases are same,so

2x+1=5

2x=5-1

2x=4

x=4/2

x=2

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