Question

Find the value of (2x+3)^2 - (2x-3)^2. *

Answer 1

Answer:

Using identity of (a+b)^2

and (a-b)^2

so ,{( 2x)^2+2x×2x×3+3^2}-{(2x)^2-2×2x×3+(3)^2}

(4x^2+12x+9)-(4x^2-12x+9).

4x^2+12x+9-4x^2+12x+9. [cancle 4x^2,-4x^2,9,-9

12+12

=24

so, the answer is 24

Hope it helped you

Plz mark me brainliest ❣️❣️

Answer 2

Answer:

using the formula

$x ^{2} - y ^{2} = (x - y)(x + y)$

[/tex]Step-by-step explanation:$(2x + 3) ^{2} - (2x - 3) ^{2}$= [2x + 3 - ( 2x - 3 ) ] [ 2x + 3 + ( 2x - 3 ) ]. =[2x + 3 - 2x + 3 ] [ 2x + 3 + 2x - 3 ]cancel: 2x, -2x; 3 , -3= ( 3 + 3 ) ( 2x + 2x )= 6 × 4x=24x

so 24x is a correct answer

I hope it will help you

plzzzz follow me