find the value of 2x,4y,y,z
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1
Answer:
y=21,x=48 ,z=84
explaination:
- 4y+75+y=180°(supplementary angles)
- 5y+75=180
- 5y=180-75
- 5y=105
- y=105/5
- y=21
4y=4(21)=84
- 4y+2x=180
- 84+2x=180
- 2x=180-84
- 2x=96
- x=96/2
- x=48
2x=2(48)=96
- 2x+z=180
- 96+z=180
- z=180-96
- z=84
Answered by
0
Answer:
no answer.............
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