Question

find the value of: 2x²y² + xy where x=2 and y= "-2"

please do this. ​

Answer 1

Step-by-step explanation:

substitute the value of x and y in the equation

$(2 \times {2}^{2} \times {( - 2)}^{2} ) + (2 \times ( - 2)) \\ = (2 \times4 \times 4) + ( - 4) \\ = 32 - 4 \\ = 28$

hope it helps

Answer 2

Answer:

2x²y² + xy = 28

where x=2 and y= -2

Step-by-step explanation:

Given: 2x²y² + xy

where x=2 and y=  -2

Put x=2 and y=  -2  in 2x²y² + xy, we get

2x²y² + xy

= 2(2)²(-2)² + (2)(-2)

= 2 × 4 × 4 - 4

= 8 × 4-4

= 32 - 4

= 28

So, 2x²y² + xy = 28 if x=2 and y=  -2.