Question

Find the value of 2y3– 3y2 + y – 1 if y = – 2

Answer 1

Answer:

-31

Step-by-step explanation:

$f(y)=2y^3-3y^2+y-1\\f(-2)=2(-2)^3 -3(-2)^2+(-2)-1\\f(-2)=2(-8)-3(4)-2-1\\f(-2)=-16-12-2-1=-31$