find the value of 2z1-3z2 where z1=3+4i and z2=3+6i
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Answer:
3-10i
Step-by-step explanation:
To find: 2z1-3z2
Given:z1=3+4i and z2=3+6i
∴putting the values of z1 and z2 in the given equation we get:
2(3+4i)-3(3+6i)
=-3-10i
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