Math, asked by RizaTwinkle, 1 month ago

Find the value of : (3^0 + 4^-1) × 2²

Answers

Answered by Anonymous
12

Solution :-

(3^0 + 4^-1) × 2²

( 1 + 1/4 ) × 2 × 2

( 4 + 1 ) × 4

5/4 × 4

5 Answer

Answered by honeygirl01
4

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 {3}^{0}  +  {4}^{ - 1}  \times  {2}^{2}

1 +  \frac{1}{4}  \times 4

 \frac{4 + 1}{4}  \times 4

 \frac{5}{4}  \times 4

5 \: is \: the \: answer

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