Question

find the value of (3‐¹×9‐¹)÷3‐²​

Answer 1

Answer:

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Answer 2

Answer:

$( {3}^{ - 1} \times {9}^{ - 1} ) \div {3}^{ - 2}$

$( {3}^{ - 1} \times {3}^{ - 2} ) \div {3}^{ - 2}$

$\frac{1}{ {3}^{1} } \times \frac{1}{ {3}^{2} } \times \frac{1}{ {3}^{ - 2} }$

$\frac{1}{3} \times \frac{1}{ {3}^{2} } \times {3}^{2}$

$\frac{1}{3}$