Math, asked by Alexander1111, 1 year ago

find the value of 3^100+3^101+3^102/3^99+3^98-3^99

Answers

Answered by sumaiyakhtar03

1

3^100+3^101+3^102/3^99+3^98-3^99

=6.7*10^48/5.73*10^46

=1.169*10^94

Your answer is

1.169*10^94

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