Question

find the value of (√3-√2)² and (3√3-2√2)(3√3+2√2)​

Answer 1

Step-by-step explanation:

(√3-√2)²=(√3)²+(√2)²-2√3√2. [(a-b)²=a²+b²-2ab]

=3+2-2√6

=5-2√6

(3√3-2√2)(3√3+2√2). [(a+b)(a-b)=a²-b²]

(3√3)²-(2√2)²

=(9x3)-(4×2)

=27-8=19

Answer 2

Answer:

5-(2√6) & (3√3)²-(2√2)² are the correct answers

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Step-by-step explanation:

1. (√3-√2)²= (√3)²+(√2)²-2(√3)(√2)

=3+2-2√6

=5-(2√6)

2. (3√3-2√2)(3√3+2√2)

=(3√3)²-(2√2)². {a²-b²=(a+b)(a-b)}