Find the value of: √(3^ −2)
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Answer:
Step-by-step explanation:
x = 3+ √8
x = (3+√8)(3-√8) / (3-√8)
x = (9 -8) / (3-√8)
x = 1/ (3 -√8)
Or we can write 1/x = (3-√8)
Put the value and find out
x² +(1/x²) = x² + (1/x)²
So x² + 1/ x² = (3 +√8)² + (3 -√8)²
= 9+6√8+8 + 9–6√8+8
= 34. Ans
hope it helps
:)
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