Math, asked by sanketj872, 3 months ago

Find the value of √3-²​

Answers

Answered by pardeshi1975
2

Step-by-step explanation:

The value of \sqrt{3}^{-2}=\dfrac{1}{3}

3

−2

=

3

1

Step-by-step explanation:

We have,

\sqrt{3}^{-2}

3

−2

To find, the value of \sqrt{3}^{-2}=?

3

−2

=?

∴ \sqrt{3}^{-2}

3

−2

=\dfrac{1}{\sqrt{3}^{2}}=

3

2

1

Using the identity,

a^{-m} =\dfrac{1}{a^{m}}a

−m

=

a

m

1

=\dfrac{1}{\sqrt{3}\times \sqrt{3}}=

3

×

3

1

=\dfrac{1}{3}=

3

1

[ ∵ \sqrt{3} \times\sqrt{3}=3

3

×

3

=3

∴The value of \sqrt{3}^{-2}=\dfrac{1}{3}

3

−2

=

3

1

Thus, the value of \sqrt{3}^{-2}=\dfrac{1}{3}

3

−2

=

3

1

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