Math, asked by arunnlg97, 3 days ago

find the value of (√3/2+i/2)^5-(√3/2-i/2)^5​

Answers

Answered by Anonymous
0

Answer:

If z=[

2

3

+

2

i

]

5

+[

2

3

2

i

]

5

, then

Answered by yourqueen001
2

Answer:

Given z = (√3/2 +i/2)5+(√3/2 -i/2)5

= (cos π/6 +i sin π/6)5+(cos π/6 -i sin π/6)5

= 2 cos 5π/6

= -√3

=> Re(z) <0, Im (z) = 0

Hence option (2) is the answer

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