Math, asked by haripoornimar, 18 days ago

find the value of 3^2005+3^2003÷3^2004-3^2002

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Answered by 93774320
0

Answer:

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Step-by-step explanation:

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Answered by shankerbhojkod
0

Answer:

3^2005 + 3^2003 ÷ 3^2004 - 3^2002

=3^2002 (3^3+3) ÷ 3^2002 (3^2-1)

=3^3+3 ÷ 3^2-1

=27 + 3÷ 9-1

=30 ÷ 8

=15:4

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