Question

Find the value of (3+√3)(3-√3)

Answer 1

$\huge\bf\red{\mid{\overline{\underline{Answer-6}}}\mid}$

This is in the form of

(a+b)(a-b)=a^2-b^2.

So,(3+√3)(3-√3)=3^2-√3^2=9-3

=6

Answer 2

$\huge\boxed{\texttt{\fcolorbox{purple}{pink}{Heya !!!}}}$

$(3 + \sqrt{3})(3 - \sqrt{3} )$

$= 3(3 - \sqrt{3} ) + \sqrt{3} (3 - \sqrt{3} )$

$= 9 - 3 \sqrt{3} + 3 \sqrt{3} - 9$

$= 0$

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