Math, asked by shilpid751, 2 months ago

find the value of 3^3×6^2/2^2×3^1/3​

Answers

Answered by GPGAMER9128
1

 {3}^{3}  \times  \frac{ {6}^{2} }{ {2}^{2} }  \times  {3}^{ \frac{1}{3} }

 {3}^{3 +  \frac{1}{3} }  \times {( \frac{6}{2} )}^{2}

 {3}^{ \frac{10}{3} }  \times  {3}^{2}

 {3}^{ \frac{10}{3}  + 2}

 {3}^{ \frac{16}{3} }

 \sqrt[3]{ {3}^{16} }

 {3}^{5}  \sqrt[3]{3}

243 \sqrt[3]{3}

350.46665 \: (approximtately)

Answered by shifshafeek
0

Answer:

3 ^ (14/3)

Step-by-step explanation:

3^ (3) * 6^ (2)

2^ (2) * 3^ (1/3)

3^ (3) * 36

4 * 3^ (1/3)

3^ (3) * 3^ (2) * 3^ (-1/3)

ON ADDING THE POWERS

3+2- (1/3) = 14/3

And there comes the answer

3 ^ (14/3)

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