find the value of 3✓34.2 using the value of 3✓34 and 3✓35
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Ifx=6−35, then find the value of x2+x21.
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x=6−35
x1=6−351×6+356+35
=36−356+35=16+35=6+35
x2+x21=(6−35)2+(6+35)2
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