Math, asked by zoyakhan78634, 10 months ago

find the value of 3/4√2×-1/2√3×2√3​

Answers

Answered by mysticd
0

Answer:

\frac{3}{4\sqrt{2}}-\frac{1}{2\sqrt{3}\times 2\sqrt{3}}=\frac{9\sqrt{2}-2}{24}

Step-by-step explanation:

\frac{3}{4\sqrt{2}}-\frac{1}{2\sqrt{3}\times 2\sqrt{3}}

=\frac{3\sqrt{2}}{4\sqrt{2}\times \sqrt{2}}-\frac{1}{12}

=\frac{3\sqrt{2}}{8}-\frac{1}{12}

=\frac{9\sqrt{2}-2}{24}

Therefore,

\frac{3}{4\sqrt{2}}-\frac{1}{2\sqrt{3}\times 2\sqrt{3}}=\frac{9\sqrt{2}-2}{24}

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Answered by vilnius
0

-\frac{1}{4}  is the answer.

Step-by-step explanation:

\frac{3}{4\sqrt{2} } ×- \frac{1}{2\sqrt{3}* 2\sqrt{3}  }

Multiplying \sqrt{2} with both numerator and denominator:

\frac{3\sqrt{2} }{4\sqrt{2}*\sqrt{2}  } ×- \frac{1}{2\sqrt{3}* 2\sqrt{3}  }

\frac{3\sqrt{2} }{4*2} ×- \frac{1}{2\sqrt{3}* 2\sqrt{3}  }

\frac{3\sqrt{2} }{8} ×- \frac{1}{4*3}

-\frac{\sqrt{2} }{32}

The factors of 32 are 2×2×2×2×2

-\frac{\sqrt{2} }{\sqrt{2*2}*\sqrt{2*2}*\sqrt{2}   }

-\frac{\sqrt{2} }{2*2*\sqrt{2} }

-\frac{\sqrt{2} }{4\sqrt{2} }

-\frac{1}{4}

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