Question

find the value of 3^(4x+1) = 27 ^(x+1)

Answer 1

Step-by-step explanation:

As given 3^4x+1=(27)^x+1

⇒3^4x+1=(33)^x+1

⇒3^4x+1=(3^3⋅(x+1))

⇒3^4x+1=3^3x+3

Now we have equation for x

⇒4x+1=3x+3

⇒4x−3x=3−1

⇒x=2