find the value of 3^4x-7-5=0
NeelamG:
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Answered by
1
is the right answer or not
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but both base is same
if base is same we cut the base
we cant cut the base but we can compare the powers
a^m = a^n
where a is base
and m and n are powers
we cut the base
nooo
why
3^4x=12. applying log b/s 4xlog3=log12 4xlog3=2log2+log3 putting the log values answer can be found......for all logs u just need to remember log10,log3 and log10......hope it helps
Answered by
0
i think it may be cube root of 4x-7-5 = 0
now , we have to find the value of x
=> ³√(4x-7-5) = 0
=> 4x -7-5 = 0³
=> 4x-7-5 = 0
=>4x = 12
=> x = 3
i hope it will help
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