Question

Find the value of √3 cosec 20° – sec 20°.

Answer 1

$\implies$

➩√3 cosec 20° - sec 20°

➩= √3/ sin 20° - 1/ cos 20°

= √3cos 20° - sin 20°/ sin 20° cos 20°

➩= 4 [√3/2 cos 20° - 1/2 sin 20° / 2 sin 20° cos ➩20°]

= 4 [ sin 60° cos 20° - cos 60° sin 20°/ sin 40°] -- ( 2 sin A cos A = sin 2A)

➩Using identity sin ( A - B ) = sin A cos B - cos A sin B

= 4 sin (60° - 20°) / sin 40°

= 4 sin 40°/ sin 40°

= 4

➩Required Answer is 4

➩

Hope This Helps You!

Answer 2

Answer:

Please refer to the attachment for the answer