Question

Find the value of √3 cosec 20° – sec 20°.​

Answer 1

Answer:

By canceling the like terms from the above expression, we get E = 4. So, we get the value of √3cosec20o−sec20o=4.

Answer 2

$\sqrt{3} (\frac{1}{sin20} ) - \frac{1}{cos20} \\=2(\frac{\frac{\sqrt{3} }{2} }{sin20}-\frac{\frac{1}{2} }{cos20} )\\=2(\frac{sin60}{sin20} -\frac{cos60}{cos20} )\\=2\frac{sin60cos20-sin20cos60}{sin20cos20} \\=2\frac{sin(60-20)}{sin20cos20}\\=2\frac{sin(40)}{sin20cos20}\\ \\=2\frac{sin2(20)}{sin20cos20}\\\\=2\frac{sin20cos20}{sin20cos20}\\\\=2(1)=2$