Find the value of √3 cosec 20° – sec 20°.
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Answered by
1
Answer:
√3 cosec 20° – sec 20°
= (√3/sin 20°) – (1/ cos 20°)
= (√3 cos 20° – sin 20°)/ sin 20° cos 20°
= 4 [√3/2 cos 20° – 1/2 sin 20°] / 2 sin 20° cos 20°
= 4 [sin 60° cos 20° – cos 60° sin 20°/ sin 40°]
Using the identity sin (A – B) = sin A cos B – cos A sin B
= 4 sin (60° – 20°) / sin 40°
= 4 (sin 40°/ sin 40°)
= 4 × 1
= 4
Answered by
1
Answer:
√3 cosec 20° - sec 20°
=(√3/sin 20°) - (1/cos 20°)
=(√3 cos 20° - sin 20°)/ sin 20° cos 20°
= 4 [√3/2 cos 20° - 1/2 sin 20°] / 2 sin 20° =
cos 20°
= 4 [sin 60° cos 20° - cos 60° sin 20°/ sin
40°]
Using the identity sin (A - B) = sin A cos B
- cos A sin B
= 4 sin (60° -20°) / sin 40°
= 4 (sin 40°/ sin 40°)
Step-by-step explanation:
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