Math, asked by kezonuto, 9 months ago

Find the value of 3 Sin ²45 + 2 cos^2 30° -cot^2 30°​

Answers

Answered by IronMan2005
1

Answer:

cos² 30° + cos² 45° + cos² 60° + cos² 90°

= (√3/2)² + (1/√2)² + (½)² + 0

= ¾ + ½ + ¼ + 0

= ¾ + ¼ + ½ + 0

= (3 + 1) /4 + ½

[ By taking L.C.M]

= 4/4 + ½

= 1 + 1/2

= (2+1)/2 = 3/2

[ By taking L.C.M]

cos² 30° + cos² 45° + cos² 60° + cos² 90° = 3/2

[cos 30° = √3/2 , cos 45° =1/√2 , cos 60° = 1/2 , cos 90° = 0]

Hence, cos² 30° + cos² 45° + cos² 60° + cos² 90° = 3/2.

HOPE THIS ANSWER WILL HELP YOU…

Answered by godenagaraju27
2

Answer:

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