Find the value of 3 Sin ²45 + 2 cos^2 30° -cot^2 30°
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cos² 30° + cos² 45° + cos² 60° + cos² 90°
= (√3/2)² + (1/√2)² + (½)² + 0
= ¾ + ½ + ¼ + 0
= ¾ + ¼ + ½ + 0
= (3 + 1) /4 + ½
[ By taking L.C.M]
= 4/4 + ½
= 1 + 1/2
= (2+1)/2 = 3/2
[ By taking L.C.M]
cos² 30° + cos² 45° + cos² 60° + cos² 90° = 3/2
[cos 30° = √3/2 , cos 45° =1/√2 , cos 60° = 1/2 , cos 90° = 0]
Hence, cos² 30° + cos² 45° + cos² 60° + cos² 90° = 3/2.
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